返回迭代器对具有的键值比大于指定的键映射的第一个元素。
iterator upper_bound(
const Key& _Key
);
const_iterator upper_bound(
const Key& _Key
) const;
参数
- _Key
参数键值用一个元素比较的排序关键字值从要搜索的映射。
返回值
解决一个元素位于映射的关键比参数键大的 iterator 或 const_iterator 或解决成功最后一个元素的位置在映射,如果与未作为项中。
如果返回值赋给 const_iterator,不能修改映射对象。如果返回值赋给 iterator,可以修改映射对象。
示例
// map_upper_bound.cpp
// compile with: /EHsc
#include <map>
#include <iostream>
int main( )
{
using namespace std;
map <int, int> m1;
map <int, int> :: const_iterator m1_AcIter, m1_RcIter;
typedef pair <int, int> Int_Pair;
m1.insert ( Int_Pair ( 1, 10 ) );
m1.insert ( Int_Pair ( 2, 20 ) );
m1.insert ( Int_Pair ( 3, 30 ) );
m1_RcIter = m1.upper_bound( 2 );
cout << "The first element of map m1 with a key "
<< "greater than 2 is: "
<< m1_RcIter -> second << "." << endl;
// If no match is found for the key, end is returned
m1_RcIter = m1. upper_bound ( 4 );
if ( m1_RcIter == m1.end( ) )
cout << "The map m1 doesn't have an element "
<< "with a key greater than 4." << endl;
else
cout << "The element of map m1 with a key > 4 is: "
<< m1_RcIter -> second << "." << endl;
// The element at a specific ___location in the map can be found
// using a dereferenced iterator addressing the ___location
m1_AcIter = m1.begin( );
m1_RcIter = m1. upper_bound ( m1_AcIter -> first );
cout << "The 1st element of m1 with a key greater than\n"
<< "that of the initial element of m1 is: "
<< m1_RcIter -> second << "." << endl;
}
要求
标头: <map>
命名空间: std