reverse_iterator::base

从其 reverse_iterator还原基础迭代器。

RandomIterator base( ) const;

返回值

基础 reverse_iterator的迭代器。

备注

与其基础迭代器处理所有反向迭代器的标识是：

&* (reverse;iterator (i)) == &* ( i – 1)。

实际上，这意味着在该反向顺序 reverse_iterator 将引用在(右侧)的迭代器在原始序列引用组件之外的元素的位置。因此，如果迭代器解决了在序列(2，4，6，8)，然后 reverse_iterator 元素6将解析该反向顺序(8，6，4，2)的元素4。

示例

// reverse_iterator_base.cpp
// compile with: /EHsc
#include <iterator>
#include <algorithm>
#include <vector>
#include <iostream>

int main( )
{
   using namespace std;
   int i;

   vector<int> vec;
   for ( i = 1 ; i < 6 ; ++i )  
   {
      vec.push_back ( 2 * i );
   }
   
   vector <int>::iterator vIter;
   cout << "The vector vec is: ( ";
   for ( vIter = vec.begin ( ) ; vIter != vec.end ( ); vIter++ )
      cout << *vIter << " ";
   cout << ")." << endl;

   vector <int>::reverse_iterator rvIter;
   cout << "The vector vec reversed is: ( ";
   for ( rvIter = vec.rbegin( ) ; rvIter != vec.rend( ); rvIter++)
      cout << *rvIter << " ";
   cout << ")." << endl;

   vector <int>::iterator pos, bpos;
   pos = find ( vec.begin ( ), vec.end ( ), 6 );
   cout << "The iterator pos points to: " << *pos << "." << endl;

   typedef reverse_iterator<vector<int>::iterator>::iterator_type it_vec_int_type;

   reverse_iterator<it_vec_int_type> rpos ( pos );
   cout << "The reverse_iterator rpos points to: " << *rpos 
        << "." << endl;

   bpos = rpos.base ( );
   cout << "The iterator underlying rpos is bpos & it points to: " 
        << *bpos << "." << endl;
}

Output

The vector vec is: ( 2 4 6 8 10 ).
The vector vec reversed is: ( 10 8 6 4 2 ).
The iterator pos points to: 6.
The reverse_iterator rpos points to: 4.
The iterator underlying rpos is bpos & it points to: 6.

要求

标头: <iterator>

命名空间: std

请参见

参考

reverse_iterator Class

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