numeric_limits::is_specialized

测试，如果类型具有定义的显式专用化模板中 numeric_limits类。

static const bool is_specialized = false;

返回值

true，如果类型具有定义的显式专用化。模板类；false，则不是。

备注

除指针类型以外的任何标量为定义模板类的显式专用化。numeric_limits

示例

// numeric_limits_is_specialized.cpp
// compile with: /EHsc
#include <iostream>
#include <limits>

using namespace std;

int main( )
{
   cout << "Whether float objects have an explicit "
        << "specialization in the class: "
        << numeric_limits<float>::is_specialized
        << endl;
   cout << "Whether float* objects have an explicit "
        << "specialization in the class: "
        << numeric_limits<float*>::is_specialized
        << endl;
   cout << "Whether int objects have an explicit "
        << "specialization in the class: "
        << numeric_limits<int>::is_specialized
        << endl;
   cout << "Whether int* objects have an explicit "
        << "specialization in the class: "
        << numeric_limits<int*>::is_specialized
        << endl;
}

要求

页眉： <限制>

命名空间: std

请参见

参考

strstreambuf 类