测试不相等的文件位置的。
bool operator!=(
const fpos<Statetype>& _Right
) const;
参数
- _Right
指示器比较的文件的位置。
返回值
true,如果文档位置不指示相等,则为 false。
备注
成员函数_Right返回 ###!(*this == )。
示例
// fpos_op_neq.cpp
// compile with: /EHsc
#include <fstream>
#include <iostream>
int main( )
{
using namespace std;
fpos<int> pos1, pos2;
ifstream file;
char c;
// Compare two fpos object
if ( pos1 != pos2 )
cout << "File position pos1 and pos2 are not equal" << endl;
else
cout << "File position pos1 and pos2 are equal" << endl;
file.open( "fpos_op_neq.txt" );
file.seekg( 0 ); // Goes to a zero-based position in the file
pos1 = file.tellg( );
file.get( c);
cout << c << endl;
// Increment pos1
pos1 += 1;
file.get( c );
cout << c << endl;
pos1 = file.tellg( ) - fpos<int>( 2);
file.seekg( pos1 );
file.get( c );
cout << c << endl;
// Increment pos1
pos1 = pos1 + fpos<int>( 1 );
file.get(c);
cout << c << endl;
pos1 -= fpos<int>( 2 );
file.seekg( pos1 );
file.get( c );
cout << c << endl;
file.close( );
}
Enter:fpos_op_neq.txt
987654321
Output
File position pos1 and pos2 are equal
9
8
9
8
8
要求
页眉: <ios>
命名空间: std