XNode.NextNode 属性

public:
 property System::Xml::Linq::XNode ^ NextNode { System::Xml::Linq::XNode ^ get(); };

public System.Xml.Linq.XNode NextNode { get; }

public System.Xml.Linq.XNode? NextNode { get; }

member this.NextNode : System.Xml.Linq.XNode

Public ReadOnly Property NextNode As XNode

属性值

包含下一个同级节点的 XNode。

示例

以下示例使用此属性循环访问节点。

XElement xmlTree = new XElement("Root",  
    new XElement("Child1", 1),  
    new XText("Some Text"),  
    new XElement("Child2",  
        2,  
        new XElement("GrandChild", "GrandChild Content")  
    ),  
    new XComment("a comment"),  
    new XElement("Child3")  
);  
XNode node = xmlTree.Element("Child2");  
do {  
    StringBuilder sb = new StringBuilder();  
    sb.Append(String.Format("NodeType: {0}", node.NodeType.ToString().PadRight(10)));  
    switch (node.NodeType)  
    {  
        case XmlNodeType.Text:  
            sb.Append((node as XText).Value);  
            break;  
        case XmlNodeType.Element:  
            sb.Append((node as XElement).Name);  
            break;  
        case XmlNodeType.Comment:  
            sb.Append((node as XComment).Value);  
            break;  
    }  
    Console.WriteLine(sb.ToString());  
}  
while ((node = node.NextNode) != null);  

Dim xmlTree As XElement = _   
        <Root>  
            <Child1>1</Child1>Some Text  
            <Child2>2  
                <GrandChild>GrandChild Content</GrandChild>  
            </Child2>  
            <!--a comment-->  
            <Child3>3</Child3>  
        </Root>  

Dim node As XNode = xmlTree.Element("Child2")  
Do  
    Dim sb As StringBuilder = New StringBuilder()  
    sb.Append(String.Format("NodeType: {0}", node.NodeType.ToString().PadRight(10)))  
    Select Case node.NodeType  
        Case XmlNodeType.Text  
            sb.Append(DirectCast(node, XText).Value)  
        Case XmlNodeType.Element  
            sb.Append(DirectCast(node, XElement).Name)  
        Case XmlNodeType.Comment  
            sb.Append(DirectCast(node, XComment).Value)  
    End Select  
    Console.WriteLine(sb.ToString())  

    node = node.NextNode  
Loop While (Not (node Is Nothing))  

该示例产生下面的输出：

NodeType: Element   Child2  
NodeType: Comment   a comment  
NodeType: Element   Child3  

注解

如果此 XNode 没有父节点，或者没有下一个节点，则此属性返回 null。

另请参阅

• LINQ to XML 概述