XNode.NextNode 属性

public:
 property System::Xml::Linq::XNode ^ NextNode { System::Xml::Linq::XNode ^ get(); };

public System.Xml.Linq.XNode NextNode { get; }

public System.Xml.Linq.XNode? NextNode { get; }

member this.NextNode : System.Xml.Linq.XNode

Public ReadOnly Property NextNode As XNode

属性值

包含下一个同级节点的 XNode。

示例

以下示例使用此属性循环访问节点。

XElement xmlTree = new XElement("Root",
    new XElement("Child1", 1),
    new XText("Some Text"),
    new XElement("Child2",
        2,
        new XElement("GrandChild", "GrandChild Content")
    ),
    new XComment("a comment"),
    new XElement("Child3")
);
XNode node = xmlTree.Element("Child2");
do {
    StringBuilder sb = new StringBuilder();
    sb.Append(String.Format("NodeType: {0}", node.NodeType.ToString().PadRight(10)));
    switch (node.NodeType)
    {
        case XmlNodeType.Text:
            sb.Append((node as XText).Value);
            break;
        case XmlNodeType.Element:
            sb.Append((node as XElement).Name);
            break;
        case XmlNodeType.Comment:
            sb.Append((node as XComment).Value);
            break;
    }
    Console.WriteLine(sb.ToString());
}
while ((node = node.NextNode) != null);

Dim xmlTree As XElement = _
        <Root>
            <Child1>1</Child1>Some Text
            <Child2>2
                <GrandChild>GrandChild Content</GrandChild>
            </Child2>
            <!--a comment-->
            <Child3>3</Child3>
        </Root>

Dim node As XNode = xmlTree.Element("Child2")
Do
    Dim sb As StringBuilder = New StringBuilder()
    sb.Append(String.Format("NodeType: {0}", node.NodeType.ToString().PadRight(10)))
    Select Case node.NodeType
        Case XmlNodeType.Text
            sb.Append(DirectCast(node, XText).Value)
        Case XmlNodeType.Element
            sb.Append(DirectCast(node, XElement).Name)
        Case XmlNodeType.Comment
            sb.Append(DirectCast(node, XComment).Value)
    End Select
    Console.WriteLine(sb.ToString())

    node = node.NextNode
Loop While (Not (node Is Nothing))

该示例产生下面的输出：

NodeType: Element   Child2
NodeType: Comment   a comment
NodeType: Element   Child3

注解

如果此 XNode 没有父节点，或者没有下一个节点，则此属性返回 null。

另请参阅

• LINQ to XML 概述