1 次元 Array 内または Array の範囲内で値が最後に見つかった位置のインデックス番号を返します。
オーバーロードの一覧
指定したオブジェクトを検索し、1 次元の Array 全体でそのオブジェクトが最後に見つかった位置のインデックス番号を返します。
[Visual Basic] Overloads Public Shared Function LastIndexOf(Array, Object) As Integer
[JScript] public static function LastIndexOf(Array, Object) : int;
指定したオブジェクトを検索し、最初の要素から指定したインデックスまでの 1 次元 Array の範囲内でそのオブジェクトが最後に見つかった位置のインデックス番号を返します。
[Visual Basic] Overloads Public Shared Function LastIndexOf(Array, Object, Integer) As Integer
[JScript] public static function LastIndexOf(Array, Object, int) : int;
指定したオブジェクトを検索し、指定したインデックスで終了する、指定した要素数を含む 1 次元 Array の範囲内でそのオブジェクトが最後に見つかった位置のインデックス番号を返します。
.NET Compact Framework でもサポート。
[Visual Basic] Overloads Public Shared Function LastIndexOf(Array, Object, Integer, Integer) As Integer
[C#] public static int LastIndexOf(Array, object, int, int);
[C++] public: static int LastIndexOf(Array*, Object*, int, int);
[JScript] public static function LastIndexOf(Array, Object, int, int) : int;
使用例
配列内で最後に見つかった指定要素のインデックスを確認する方法を次のコード例で示します。 LastIndexOf メソッドは逆方向検索であるため、count が (startIndex- 配列の下限 + 1) 以下である必要があります。
Imports System
Imports Microsoft.VisualBasic
Public Class SamplesArray
Public Shared Sub Main()
' Creates and initializes a new Array with three elements of
' the same value.
Dim myArray As Array = Array.CreateInstance(GetType(String), 12)
myArray.SetValue("the", 0)
myArray.SetValue("quick", 1)
myArray.SetValue("brown", 2)
myArray.SetValue("fox", 3)
myArray.SetValue("jumps", 4)
myArray.SetValue("over", 5)
myArray.SetValue("the", 6)
myArray.SetValue("lazy", 7)
myArray.SetValue("dog", 8)
myArray.SetValue("in", 9)
myArray.SetValue("the", 10)
myArray.SetValue("barn", 11)
' Displays the values of the Array.
Console.WriteLine("The Array contains the following values:")
PrintIndexAndValues(myArray)
' Searches for the last occurrence of the duplicated value.
Dim myString As String = "the"
Dim myIndex As Integer = Array.LastIndexOf(myArray, myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", _
myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first
' section of the Array.
myIndex = Array.LastIndexOf(myArray, myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start " _
+ "and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section
' of the Array. Note that the start index is greater than the end
' index because the search is done backward.
myIndex = Array.LastIndexOf(myArray, myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 5 " _
+ "and index 10 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myArray As Array)
Dim i As Integer
For i = myArray.GetLowerBound(0) To myArray.GetUpperBound(0)
Console.WriteLine(ControlChars.Tab + "[{0}]:" + ControlChars.Tab _
+ "{1}", i, myArray.GetValue(i))
Next i
End Sub
End Class
' This code produces the following output.
'
' The Array contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 5 and index 10 is at index 10.
[C#]
using System;
public class SamplesArray {
public static void Main() {
// Creates and initializes a new Array with three elements of the same value.
Array myArray=Array.CreateInstance( typeof(String), 12 );
myArray.SetValue( "the", 0 );
myArray.SetValue( "quick", 1 );
myArray.SetValue( "brown", 2 );
myArray.SetValue( "fox", 3 );
myArray.SetValue( "jumps", 4 );
myArray.SetValue( "over", 5 );
myArray.SetValue( "the", 6 );
myArray.SetValue( "lazy", 7 );
myArray.SetValue( "dog", 8 );
myArray.SetValue( "in", 9 );
myArray.SetValue( "the", 10 );
myArray.SetValue( "barn", 11 );
// Displays the values of the Array.
Console.WriteLine( "The Array contains the following values:" );
PrintIndexAndValues( myArray );
// Searches for the last occurrence of the duplicated value.
String myString = "the";
int myIndex = Array.LastIndexOf( myArray, myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the Array.
myIndex = Array.LastIndexOf( myArray, myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the Array.
// Note that the start index is greater than the end index because the search is done backward.
myIndex = Array.LastIndexOf( myArray, myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 5 and index 10 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( Array myArray ) {
for ( int i = myArray.GetLowerBound(0); i <= myArray.GetUpperBound(0); i++ )
Console.WriteLine( "\t[{0}]:\t{1}", i, myArray.GetValue( i ) );
}
}
/*
This code produces the following output.
The Array contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 5 and index 10 is at index 10.
*/
[C++]
#using <mscorlib.dll>
using namespace System;
void PrintIndexAndValues( Array* myArray );
void main() {
// Creates and initializes a new Array instance with three elements of the same value.
Array* myArray = Array::CreateInstance( __typeof(String), 12 );
myArray->SetValue( S"the", 0 );
myArray->SetValue( S"quick", 1 );
myArray->SetValue( S"brown", 2 );
myArray->SetValue( S"fox", 3 );
myArray->SetValue( S"jumped", 4 );
myArray->SetValue( S"over", 5 );
myArray->SetValue( S"the", 6 );
myArray->SetValue( S"lazy", 7 );
myArray->SetValue( S"dog", 8 );
myArray->SetValue( S"in", 9 );
myArray->SetValue( S"the", 10 );
myArray->SetValue( S"barn", 11 );
// Displays the values of the Array.
Console::WriteLine( "The Array instance contains the following values:" );
PrintIndexAndValues( myArray );
// Searches for the last occurrence of the duplicated value.
String* myString = "the";
int myIndex = Array::LastIndexOf( myArray, myString );
Console::WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, __box(myIndex) );
// Searches for the last occurrence of the duplicated value in the first section of the Array.
myIndex = Array::LastIndexOf( myArray, myString, 8 );
Console::WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, __box(myIndex));
// Searches for the last occurrence of the duplicated value in a section of the Array.
// Note that the start index is greater than the end index because the search is done backward.
myIndex = Array::LastIndexOf( myArray, myString, 10, 6 );
Console::WriteLine( "The last occurrence of \"{0}\" between index 5 and index 10 is at index {1}.", myString, __box(myIndex));
}
void PrintIndexAndValues( Array* myArray ) {
for ( int i = myArray->GetLowerBound(0); i <= myArray->GetUpperBound(0); i++ )
Console::WriteLine( "\t[{0}]:\t{1}", __box(i), myArray->GetValue( i ) );
}
/*
This code produces the following output.
The Array instance contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumped
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 5 and index 10 is at index 10.
*/
[JScript]
import System;
// Creates and initializes a new Array with three elements of the same value.
var myArray : System.Array= System.Array.CreateInstance( System.String, 12 );
myArray.SetValue( "the", 0 );
myArray.SetValue( "quick", 1 );
myArray.SetValue( "brown", 2 );
myArray.SetValue( "fox", 3 );
myArray.SetValue( "jumped", 4 );
myArray.SetValue( "over", 5 );
myArray.SetValue( "the", 6 );
myArray.SetValue( "lazy", 7 );
myArray.SetValue( "dog", 8 );
myArray.SetValue( "in", 9 );
myArray.SetValue( "the", 10 );
myArray.SetValue( "barn", 11 );
// Displays the values of the Array.
Console.WriteLine( "The Array contains the following values:" );
PrintIndexAndValues( myArray );
// Searches for the last occurrence of the duplicated value.
var myString : String = "the";
var myIndex : int = System.Array.LastIndexOf( myArray, myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the Array.
myIndex = System.Array.LastIndexOf( myArray, myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the Array.
// Note that the start index is greater than the end index because the search is done backward.
myIndex = System.Array.LastIndexOf( myArray, myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 5 and index 10 is at index {1}.", myString, myIndex );
function PrintIndexAndValues( myArray : System.Array ) {
for ( var i : int = myArray.GetLowerBound(0); i <= myArray.GetUpperBound(0); i++ )
Console.WriteLine( "\t[{0}]:\t{1}", i, myArray.GetValue( i ) );
}
/*
This code produces the following output.
The Array contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumped
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 5 and index 10 is at index 10.
*/